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职友集>程序员面试题 > 北京爱恩科技发展有限公司笔试考题

北京爱恩科技发展有限公司笔试考题

2014-06-09 06:30:01 阅读( 51 )

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标签:程序员面试题

VISUAL BASIC SECTION

Q1 : Grade yourself on your Visual Basic Skill ?
1 – poor …….. 10- Advance player

Ans:

Q2 : Declare Function Multiply_Add Lib “test” (ByRef A as integer ,VeRef B as integer , ByVal c as integer ) as integer

Q2.1: Explain what is Declare Function used for ?

Ans :

Q2.2 : Explain the difference between ByRef and ByVal ?

Ans :

Q3 : Is Visual Basic a COMPILER or an INTERPERTER ?

Ans

C++ SECTION

Q4 :
int iVal1 = 0, iVal2 = 0;
int * ipVal;

ipVal = &iVal1; What is the Value of ipVal = *ipVal =

ipVal = (int*)iVal1; What is the Value of ipVal = *ipVal =

iVal2 = (int)&iVal1; What is the Value of ipVal = *ipVal =

Q5:
void SwapAB(int A, int B)
{
A=B;
B=A;
}

int main()
{
int A,B;
A=1;
B=2;
SwapAB(A,B);
return 0;// A= ?, B= ?
}

What is the value of A and B ?

What is the difference between STRUCTURE and OBJECT ORIENTED PROGRAMMING ?

What is the difference between C and C++ ?

What is an interpreter ?
.

Q6. Step through the following C code and answer the questions

void FillMem(unsigned char *pData, unsigned char len)
{
while (len–) *pData++ = len;
}

void main()
{
unsigned char buffer1[8];
unsigned char buffer2[8];
unsigned char * pData;
unsigned char cnt1, cnt2;

for (cnt1 = 0; cnt1 < 8; cnt1++)
buffer1[cnt1] = 0xFF;

for (cnt1 = 0; cnt1 < 8; cnt1++)
buffer2[cnt1] = 0xFF;

for (cnt1 = 0, cnt2 = 4; cnt1 < 4; cnt1++, cnt2--)
buffer1[cnt1] = cnt1;
buffer2[cnt2] = cnt2;

/***************************************************************
Q What is the content of buffer1 & buffer2 ?
buffer1[0] = ?? buffer2[0] = ??
buffer1[1] = ?? buffer2[1] = ??
buffer1[2] = ?? buffer2[2] = ??
buffer1[3] = ?? buffer2[3] = ??
****************************************************************/

for (cnt1 = 0; cnt1 < 8; cnt1++)
buffer1[cnt1] = 0xFF;

FillMem(&buffer1[0], 4);

/***************************************************************
Q. What is the content of buffer1 ?
buffer1[0] = ??
buffer1[1] = ??
buffer1[2] = ??
buffer1[3] = ??
****************************************************************/

for (cnt1 = 0; cnt1 < 8; cnt1++)
buffer1[cnt1] = 0xFF;

pData = &buffer1[4];
pData = pData - 2;

for (cnt1 = 0; cnt1 < 2; cnt1++)
*pData++ = cnt1;

/***************************************************************
Q. What is the content of buffer1 ?
buffer1[0] = ??
buffer1[1] = ??
buffer1[2] = ??
buffer1[3] = ??
****************************************************************/

}

Visual Basic / C++ Section:

You can use C/C++ or Visual Basic to do the following

Please write a simple function to access the momory card 8x8 bytes
The input parameter for memory location is between 0-63
If user want to write ‘1’ at the memory location 9, then this function will write ‘1’ at cell (1,1)

Eg.
MemAccess(9,1); // MemAccess(int Position, int Value);
MemAccess(2,5);

Result

01234567
0
1
2
3
4
5
6
7

Note: you can use array type to define this memory card.
Eg.
Int MemoryCard[8][8]; // Array definition in C

{
}

BACK TO FOUNDATION

1 BYTE = _________BITS (based on 8 bits processor)

1 INTEGER = _______BYTES (based on 8 bits processor)

1 LONG = _________BYTES (based on 8 bits processor)

8051 ASSEMBLY LANGUAGE PROGRAMMING

Add a comment on each line !

MOV DPTR,#atable
MOV A,R7
MOVC A, @A+DPTR
CJNE A,#EEPDELIVERYSTATE,_JUMP1
RET

_JUMP1:
MOV R6,A
MOV A,R7
INC A
MOVC A, @A+DPTR
MOV DPL,A
MOV DPH,R6

POP ACC
POP ACC
CLR A
JMP @A+DPTR

Explain what is the function ?

JAVA SECTION:

Q 1. Construct a Java program to do the following
(if you do this question, you do not have to answer Q2, Q3 and Q4):

byte b =
byte pos = ;
bu.IsBitOn(b, pos);
b = 4;
bu.IsBitOn(b, pos);

Result:

> Byte = 5, Bit at position 0 is on.
> Byte = 4, Bit at position 0 is off

Eg.
5 = 00000101
7 6 5 4 3 2 1 0
00000101

Bit at position 0 is on

Q 2. Explain why Java program can be easily run on different platforms/operating systems.

Q 3. Describe the structure of a Class in Java

Q 4. Explain Inheritance and Overloaded Function in Java
上海-VC3

VISUAL BASIC SECTION

Q1 : Grade yourself on your Visual Basic Skill ?
1 – poor …….. 10- Advance player

Ans:

Q2 : Declare Function Multiply_Add Lib “test” (ByRef A as integer ,VeRef B as integer , ByVal c as integer ) as integer

Q2.1: Explain what is Declare Function used for ?

Ans :

Q2.2 : Explain the difference between ByRef and ByVal ?

Ans :

Q3 : Is Visual Basic a COMPILER or an INTERPERTER ?

Ans

C++ SECTION

Q4 :
int iVal1 = 0, iVal2 = 0;
int * ipVal;

ipVal = &iVal1; What is the Value of ipVal = *ipVal =

ipVal = (int*)iVal1; What is the Value of ipVal = *ipVal =

iVal2 = (int)&iVal1; What is the Value of ipVal = *ipVal =

Q5:
void SwapAB(int A, int B)
{
A=B;
B=A;
}

int main()
{
int A,B;
A=1;
B=2;
SwapAB(A,B);
return 0;// A= ?, B= ?
}

What is the value of A and B ?

What is the difference between STRUCTURE and OBJECT ORIENTED PROGRAMMING ?

What is the difference between C and C++ ?

What is an interpreter ?
.

Q6. Step through the following C code and answer the questions

void FillMem(unsigned char *pData, unsigned char len)
{
while (len–) *pData++ = len;
}

void main()
{
unsigned char buffer1[8];
unsigned char buffer2[8];
unsigned char * pData;
unsigned char cnt1, cnt2;

for (cnt1 = 0; cnt1 < 8; cnt1++)
buffer1[cnt1] = 0xFF;

for (cnt1 = 0; cnt1 < 8; cnt1++)
buffer2[cnt1] = 0xFF;

for (cnt1 = 0, cnt2 = 4; cnt1 < 4; cnt1++, cnt2--)
buffer1[cnt1] = cnt1;
buffer2[cnt2] = cnt2;

/***************************************************************
Q What is the content of buffer1 & buffer2 ?
buffer1[0] = ?? buffer2[0] = ??
buffer1[1] = ?? buffer2[1] = ??
buffer1[2] = ?? buffer2[2] = ??
buffer1[3] = ?? buffer2[3] = ??
****************************************************************/

for (cnt1 = 0; cnt1 < 8; cnt1++)
buffer1[cnt1] = 0xFF;

FillMem(&buffer1[0], 4);

/***************************************************************
Q. What is the content of buffer1 ?
buffer1[0] = ??
buffer1[1] = ??
buffer1[2] = ??
buffer1[3] = ??
****************************************************************/

for (cnt1 = 0; cnt1 < 8; cnt1++)
buffer1[cnt1] = 0xFF;

pData = &buffer1[4];
pData = pData - 2;

for (cnt1 = 0; cnt1 < 2; cnt1++)
*pData++ = cnt1;

/***************************************************************
Q. What is the content of buffer1 ?
buffer1[0] = ??
buffer1[1] = ??
buffer1[2] = ??
buffer1[3] = ??
****************************************************************/

}

Visual Basic / C++ Section:

You can use C/C++ or Visual Basic to do the following

Please write a simple function to access the momory card 8x8 bytes
The input parameter for memory location is between 0-63
If user want to write ‘1’ at the memory location 9, then this function will write ‘1’ at cell (1,1)

Eg.
MemAccess(9,1); // MemAccess(int Position, int Value);
MemAccess(2,5);

Result

01234567
0
1
2
3
4
5
6
7

Note: you can use array type to define this memory card.
Eg.
Int MemoryCard[8][8]; // Array definition in C

{
}

BACK TO FOUNDATION

1 BYTE = _________BITS (based on 8 bits processor)

1 INTEGER = _______BYTES (based on 8 bits processor)

1 LONG = _________BYTES (based on 8 bits processor)

8051 ASSEMBLY LANGUAGE PROGRAMMING

Add a comment on each line !

MOV DPTR,#atable
MOV A,R7
MOVC A, @A+DPTR
CJNE A,#EEPDELIVERYSTATE,_JUMP1
RET

_JUMP1:
MOV R6,A
MOV A,R7
INC A
MOVC A, @A+DPTR
MOV DPL,A
MOV DPH,R6

POP ACC
POP ACC
CLR A
JMP @A+DPTR

Explain what is the function ?

JAVA SECTION:

Q 1. Construct a Java program to do the following
(if you do this question, you do not have to answer Q2, Q3 and Q4):

byte b =
byte pos = ;
bu.IsBitOn(b, pos);
b = 4;
bu.IsBitOn(b, pos);

Result:

> Byte = 5, Bit at position 0 is on.
> Byte = 4, Bit at position 0 is off

Eg.
5 = 00000101
7 6 5 4 3 2 1 0
00000101

Bit at position 0 is on

Q 2. Explain why Java program can be easily run on different platforms/operating systems.

Q 3. Describe the structure of a Class in Java

Q 4. Explain Inheritance and Overloaded Function in Java

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