VB笔试题(英文的)

VISUAL BASIC SECTION

Q1 : Grade yourself on your Visual Basic Skill ?

1 ¨C poor ¡­¡­.. 10- Advance player

Ans:

Q2 : Declare Function Multiply_Add Lib ¡°test¡± (ByRef A as integer ,VeRef B as integer , ByVal c as integer ) as integer

Q2.1: Explain what is Declare Function used for ?

Ans :

Q2.2 : Explain the difference between ByRef and ByVal ?

Ans :

Q3 : Is Visual Basic a COMPILER or an INTERPERTER ?

Ans

C++ SECTION

Q4 :

int iVal1 = 0, iVal2 = 0;

int * ipVal;

ipVal = &iVal1; What is the Value of ipVal = *ipVal =

ipVal = (int*)iVal1; What is the Value of ipVal = *ipVal =

iVal2 = (int)&iVal1; What is the Value of ipVal = *ipVal =

Q5:

void SwapAB(int A, int B)

{

A=B;

B=A;

}

int main()

{

int A,B;

A=1;

B=2;

SwapAB(A,B);

return 0; // A= ?, B= ?

}

What is the value of A and B ?

What is the difference between STRUCTURE and OBJECT ORIENTED PROGRAMMING ?

What is the difference between C and C++ ?

What is an interpreter ?

.

Q6. Step through the following C code and answer the questions

void FillMem(unsigned char *pData, unsigned char len)

{

while (len–) *pData++ = len;

}

void main()

{

unsigned char buffer1[8];

unsigned char buffer2[8];

unsigned char * pData;

unsigned char cnt1, cnt2;

for (cnt1 = 0; cnt1 < 8; cnt1++)

buffer1[cnt1] = 0xFF;

for (cnt1 = 0; cnt1 < 8; cnt1++)

buffer2[cnt1] = 0xFF;

for (cnt1 = 0, cnt2 = 4; cnt1 < 4; cnt1++, cnt2–)

buffer1[cnt1] = cnt1;

buffer2[cnt2] = cnt2;

/***************************************************************

Q What is the content of buffer1 & buffer2 ?

buffer1[0] = ?? buffer2[0] = ??

buffer1[1] = ?? buffer2[1] = ??

buffer1[2] = ?? buffer2[2] = ??

buffer1[3] = ?? buffer2[3] = ??

****************************************************************/

for (cnt1 = 0; cnt1 < 8; cnt1++)

buffer1[cnt1] = 0xFF;

FillMem(&buffer1[0], 4);

/***************************************************************

Q. What is the content of buffer1 ?

buffer1[0] = ??

buffer1[1] = ??

buffer1[2] = ??

buffer1[3] = ??

****************************************************************/

for (cnt1 = 0; cnt1 < 8; cnt1++)

buffer1[cnt1] = 0xFF;

pData = &buffer1[4];

pData = pData – 2;

for (cnt1 = 0; cnt1 < 2; cnt1++)

*pData++ = cnt1;

/***************************************************************

Q. What is the content of buffer1 ?

buffer1[0] = ??

buffer1[1] = ??

buffer1[2] = ??

buffer1[3] = ??

****************************************************************/

}

Visual Basic / C++ Section:

You can use C/C++ or Visual Basic to do the following

Please write a simple function to access the momory card 8×8 bytes

The input parameter for memory location is between 0-63

If user want to write ¡®1¡¯ at the memory location 9, then this function will write ¡®1¡¯ at cell (1,1)

Eg.

MemAccess(9,1); // MemAccess(int Position, int Value);

MemAccess(2,5);

Result

0

1

2

3

4

5

6

7

0

1

2

3

4

5

6

7

Note: you can use array type to define this memory card.

Eg.

Int MemoryCard[8][8]; // Array definition in C

{

}

BACK TO FOUNDATION

1 BYTE = _________BITS (based on 8 bits processor)

1 INTEGER = _______BYTES (based on 8 bits processor)

1 LONG = _________BYTES (based on 8 bits processor)

8051 ASSEMBLY LANGUAGE PROGRAMMING

Add a comment on each line !

MOV DPTR,#atable

MOV A,R7

MOVC A, @A+DPTR

CJNE A,#EEPDELIVERYSTATE,_JUMP1

RET

_JUMP1:

MOV R6,A

MOV A,R7

INC A

MOVC A, @A+DPTR

MOV DPL,A

MOV DPH,R6

POP ACC

POP ACC

CLR A

JMP @A+DPTR

Explain what is the function ?